Compare the x and y bond lengths in the follo | vedclass

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(A) In Structure $1$ ($H_2S_2O_4$,dithionous acid),both sulfur atoms are in the $+3$ oxidation state. In Structure $2$ ($H_2S_2O_5$,disulfurous acid),

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$x > y$

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(A) In Structure $1$ ($H_2S_2O_4$,dithionous acid),both sulfur atoms are in the $+3$ oxidation state. In Structure $2$ ($H_2S_2O_5$,disulfurous acid),one sulfur atom is in the $+5$ oxidation state and the other is in the $+3$ oxidation state. An increase in the oxidation state of an atom leads to a decrease in its covalent radius due to a higher effective nuclear charge. Therefore,the $S-S$ bond length $y$ in Structure $2$ is shorter than the $S-S$ bond length $x$ in Structure $1$ because of the higher oxidation state of the sulfur atom in Structure $2$. Thus,$x > y$.

Compare the $x$ and $y$ bond lengths in the following molecules:
Structure $1$: $HO-S(=O)-S(=O)-OH$ (where $x$ is the $S-S$ bond length)
Structure $2$: $HO-S(=O)_2-S(=O)-OH$ (where $y$ is the $S-S$ bond length)

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Compare the $x$ and $y$ bond lengths in the following molecules:Structure $1$: $HO-S(=O)-S(=O)-OH$ (where $x$ is the $S-S$ bond length)Structure $2$: $HO-S(=O)_2-S(=O)-OH$ (where $y$ is the $S-S$ bond length)